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	<title>Comments on: Inquisitor 106 &#8211; Pared Down by Kea</title>
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	<link>http://www.fifteensquared.net/2009/01/16/inquisitor-106-pared-down-by-kea/</link>
	<description>Never knowingly undersolved.</description>
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		<title>By: Wil Ransome</title>
		<link>http://www.fifteensquared.net/2009/01/16/inquisitor-106-pared-down-by-kea/#comment-65799</link>
		<dc:creator>Wil Ransome</dc:creator>
		<pubDate>Thu, 29 Jan 2009 17:49:59 +0000</pubDate>
		<guid isPermaLink="false">http://fifteensquared.net/?p=4848#comment-65799</guid>
		<description><![CDATA[I didn&#039;t do this puzzle but the grid construction looks quite brilliant, and it looks as if a huge amount of work has gone into the blog. I hope the small number of responses doesn&#039;t correcpond to the number of people who appreciated it.

The two transformations are equivalent to a single reflection, in the diagonal from bottom left to top right.]]></description>
		<content:encoded><![CDATA[<p>I didn&#8217;t do this puzzle but the grid construction looks quite brilliant, and it looks as if a huge amount of work has gone into the blog. I hope the small number of responses doesn&#8217;t correcpond to the number of people who appreciated it.</p>
<p>The two transformations are equivalent to a single reflection, in the diagonal from bottom left to top right.</p>
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		<title>By: rayfolwell</title>
		<link>http://www.fifteensquared.net/2009/01/16/inquisitor-106-pared-down-by-kea/#comment-64049</link>
		<dc:creator>rayfolwell</dc:creator>
		<pubDate>Sun, 18 Jan 2009 11:41:26 +0000</pubDate>
		<guid isPermaLink="false">http://fifteensquared.net/?p=4848#comment-64049</guid>
		<description><![CDATA[PARED DOWN is a hompophone of PAIRED DOWN and the down answers are paired with the across ones.

This puzzle was too hard for us in the aftermath of New Year.]]></description>
		<content:encoded><![CDATA[<p>PARED DOWN is a hompophone of PAIRED DOWN and the down answers are paired with the across ones.</p>
<p>This puzzle was too hard for us in the aftermath of New Year.</p>
]]></content:encoded>
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		<title>By: HolyGhost</title>
		<link>http://www.fifteensquared.net/2009/01/16/inquisitor-106-pared-down-by-kea/#comment-63753</link>
		<dc:creator>HolyGhost</dc:creator>
		<pubDate>Fri, 16 Jan 2009 10:42:55 +0000</pubDate>
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		<description><![CDATA[The transformation mentioned is simply a reflection in the TR-BL diagonal.  This implies that when the TL triangle above that diagonal is filled in with words whose reversals are also words, the BR triangle below that diagonal automatically sorts itself out.  But still - no mean feat!]]></description>
		<content:encoded><![CDATA[<p>The transformation mentioned is simply a reflection in the TR-BL diagonal.  This implies that when the TL triangle above that diagonal is filled in with words whose reversals are also words, the BR triangle below that diagonal automatically sorts itself out.  But still &#8211; no mean feat!</p>
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		<title>By: Colin Blackburn</title>
		<link>http://www.fifteensquared.net/2009/01/16/inquisitor-106-pared-down-by-kea/#comment-63741</link>
		<dc:creator>Colin Blackburn</dc:creator>
		<pubDate>Fri, 16 Jan 2009 08:50:40 +0000</pubDate>
		<guid isPermaLink="false">http://fifteensquared.net/?p=4848#comment-63741</guid>
		<description><![CDATA[A rotation through -pi/2 followed by a reflection in h is just that, a compound of the two transformations. You could achieve the same result with other compounds of transformations.

Remarkable grid though!]]></description>
		<content:encoded><![CDATA[<p>A rotation through -pi/2 followed by a reflection in h is just that, a compound of the two transformations. You could achieve the same result with other compounds of transformations.</p>
<p>Remarkable grid though!</p>
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