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	<title>Comments on: Financial Times 13,838 &#8211; Crux</title>
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	<link>http://www.fifteensquared.net/2011/11/10/financial-times-13838-crux/</link>
	<description>Never knowingly undersolved.</description>
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		<title>By: Pelham Barton</title>
		<link>http://www.fifteensquared.net/2011/11/10/financial-times-13838-crux/#comment-174022</link>
		<dc:creator>Pelham Barton</dc:creator>
		<pubDate>Thu, 10 Nov 2011 14:29:20 +0000</pubDate>
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		<description><![CDATA[Thanks Crux for the puzzle and Sil for the blog.

28ac: I agree with the criticism. The time honoured solution of starting &quot;I&#039;ll come&quot; would give a perfectly good surface here.

24dn: I take Sil&#039;s point. I would more naturally say that &quot;everyone&quot; starts &lt;i&gt;with&lt;/i&gt; an E. I would call it a blemish, rather than a serious error.

26dn: I think &quot;covered in&quot; is just an indication for &quot;after&quot; in a down clue.]]></description>
		<content:encoded><![CDATA[<p>Thanks Crux for the puzzle and Sil for the blog.</p>
<p>28ac: I agree with the criticism. The time honoured solution of starting &#8220;I&#8217;ll come&#8221; would give a perfectly good surface here.</p>
<p>24dn: I take Sil&#8217;s point. I would more naturally say that &#8220;everyone&#8221; starts <i>with</i> an E. I would call it a blemish, rather than a serious error.</p>
<p>26dn: I think &#8220;covered in&#8221; is just an indication for &#8220;after&#8221; in a down clue.</p>
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		<title>By: Sil van den Hoek</title>
		<link>http://www.fifteensquared.net/2011/11/10/financial-times-13838-crux/#comment-173990</link>
		<dc:creator>Sil van den Hoek</dc:creator>
		<pubDate>Thu, 10 Nov 2011 12:01:39 +0000</pubDate>
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		<description><![CDATA[Well, David, for me, it starts &quot;with&quot; an and ends &quot;in&quot; an E.
Correct me if I&#039;m wrong.

Indeed, the cryptic grammar in 28ac is not right. We had a few discussions on that recently in the Guardian blogs. But I did not want to flag it up again. &quot;I must come in last to get topmost decoration&quot; would have been a way to solve this.]]></description>
		<content:encoded><![CDATA[<p>Well, David, for me, it starts &#8220;with&#8221; an and ends &#8220;in&#8221; an E.<br />
Correct me if I&#8217;m wrong.</p>
<p>Indeed, the cryptic grammar in 28ac is not right. We had a few discussions on that recently in the Guardian blogs. But I did not want to flag it up again. &#8220;I must come in last to get topmost decoration&#8221; would have been a way to solve this.</p>
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		<title>By: David</title>
		<link>http://www.fifteensquared.net/2011/11/10/financial-times-13838-crux/#comment-173956</link>
		<dc:creator>David</dc:creator>
		<pubDate>Thu, 10 Nov 2011 07:23:08 +0000</pubDate>
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		<description><![CDATA[Also thanks for the blog Sil, but I cannot understand the problem in 24D. &#039;Everyone&#039; does start in an E, doesn&#039;t it?]]></description>
		<content:encoded><![CDATA[<p>Also thanks for the blog Sil, but I cannot understand the problem in 24D. &#8216;Everyone&#8217; does start in an E, doesn&#8217;t it?</p>
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	<item>
		<title>By: David</title>
		<link>http://www.fifteensquared.net/2011/11/10/financial-times-13838-crux/#comment-173955</link>
		<dc:creator>David</dc:creator>
		<pubDate>Thu, 10 Nov 2011 07:20:20 +0000</pubDate>
		<guid isPermaLink="false">http://fifteensquared.net/?p=36550#comment-173955</guid>
		<description><![CDATA[28A) I come in last and get topmost decoration (6)

Isn&#039;t this a liberty by the setter? I thought the grammar in the cryptic reading was not correct.

1A) PATIENT (invalid) less I (one) - For PATIENT, the same clue would work with licence and invalid interchanged!

Loved most surfaces except for 30A.]]></description>
		<content:encoded><![CDATA[<p>28A) I come in last and get topmost decoration (6)</p>
<p>Isn&#8217;t this a liberty by the setter? I thought the grammar in the cryptic reading was not correct.</p>
<p>1A) PATIENT (invalid) less I (one) &#8211; For PATIENT, the same clue would work with licence and invalid interchanged!</p>
<p>Loved most surfaces except for 30A.</p>
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